The de Broglie wavelength of an electron having kinetic energy \( E \) is \( \lambda \). If the kinetic energy of electron becomes \( \dfrac{E}{4} \), then its de-Broglie wavelength will be:
\( 2\lambda \)
\( \dfrac{\lambda}{\sqrt{2}} \)
\( \sqrt{2}\lambda \)
\( \dfrac{\lambda}{2} \)