The electric field at a point associated with a light wave is given by \( E = 200 \left[\sin(6 \times 10^{15} )t + \sin(9 \times 10^{15} )t\right] \, \text{V m}^{-1} \)
Given: \( h = 4.14 \times 10^{-15} \, \text{eV s} \)
If this light falls on a metal surface having a work function of \( 2.50 \, \text{eV} \), the maximum kinetic energy of the photoelectrons will be: