A hydrogen atom in its ground state absorbs \( 10.2 \, \text{eV} \) of energy. The angular momentum of electron of the hydrogen atom will increase by the value of: (Given, Planck’s constant \( = 6.6 \times 10^{-34} \, \text{J s} \).)
\( 2.10 \times 10^{-34} \, \text{J s} \)
\( 1.05 \times 10^{-34} \, \text{J s} \)
\( 3.15 \times 10^{-34} \, \text{J s} \)
\( 4.2 \times 10^{-34} \, \text{J s} \)
