When a light of a given wavelength falls on a metallic surface the stopping potential for photoelectrons is \( 3.2 \, \text{V} \). If a second light having wavelength twice of first light is used, the stopping potential drops to \( 0.7 \, \text{V} \). The wavelength of first light is __________ m.
\( (h = 6.63 \times 10^{-34} \, \text{J}\cdot\text{s}, \; e = 1.6 \times 10^{-19} \, \text{C}, \; c = 3 \times 10^{8} \, \text{m/s}) \)