A star has \( 100\% \) helium composition. It starts to convert three \( ^4\text{He} \) into one \( ^{12}\text{C} \) via triple alpha process as \( ^4\text{He} + ^4\text{He} + ^4\text{He} \rightarrow ^{12}\text{C} + Q \). The mass of the star is \( 2.0 \times 10^{32} \, \text{kg} \) and it generates energy at the rate of \( 5.808 \times 10^{30} \, \text{W} \). The rate of converting these \( ^4\text{He} \) to \( ^{12}\text{C} \) is \( n \times 10^{42} \, \text{s}^{-1} \), where \( n \) is _______.
[Take, mass of \( ^4\text{He} = 4.0026 \, \text{u} \) , mass of \( ^{12}\text{C} = 12 \, \text{u} \) ]