A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as:
\( \lambda_{\alpha} < \lambda_{p} < \lambda_{e} \)
\( \lambda_{e} > \lambda_{\alpha} > \lambda_{p} \)
\( \lambda_{p} > \lambda_{e} > \lambda_{\alpha} \)
\( \lambda_{p} < \lambda_{e} < \lambda_{\alpha} \)