The de Broglie wavelength of a molecule in a gas at room temperature \( (300 \, \text{K}) \) is \( \lambda_1 \). If the temperature of the gas is increased to \( 600 \, \text{K} \), then the de Broglie wavelength of the same gas molecule becomes.
\( \dfrac{1}{\sqrt{2}} \lambda_1 \)
\( 2\lambda_1 \)
\( \dfrac{1}{2}\lambda_1 \)
\( \sqrt{2}\lambda_1 \)