The energy released when \( \frac{7}{17.13} \) \( \text{kg} \) of \( {}^{7}_{3}\mathrm{Li} \) is converted into \( {}^{4}_{2}\mathrm{He} \) by proton bombardment is \( \alpha \times 10^{32} \) \( \text{eV} \). The value of \( \alpha \) is _______. (Nearest integer) (Mass of \( {}^{7}_{3}\mathrm{Li} = 7.0183\,u \), mass of \( {}^{4}_{2}\mathrm{He} = 4.0004\,u \), mass of proton \( = 1.008\,u \) and \( 1u = 931\,\mathrm{MeV}/c^{2} \) and Avogadro number \( = 6.0 \times 10^{23} \))