\( \dfrac{1}{3^2 - 1} + \dfrac{1}{5^2 - 1} + \dfrac{1}{7^2 - 1} + \ldots + \dfrac{1}{(201)^2 - 1} \) is equal to:
\( \dfrac{99}{400} \)
\( \dfrac{25}{101} \)
\( \dfrac{101}{404} \)
\( \dfrac{101}{408} \)