The sum \( 1 + 2 \cdot 3 + 3 \cdot 3^{2} + \ldots + 10 \cdot 3^{9} \) is equal to:
\( \frac{2 \cdot 3^{12} + 10}{4} \)
\( \frac{19 \cdot 3^{10} + 1}{4} \)
\( 5 \cdot 3^{10} - 2 \)
\( \frac{9 \cdot 3^{10} + 1}{2} \)