The sum of the infinite series \( 1 + \frac{5}{6} + \frac{12}{6^2} + \frac{22}{6^3} + \frac{35}{6^4} + \frac{51}{6^5} + \frac{70}{6^6} + \cdots \) is equal to:
\( \frac{425}{216} \)
\( \frac{429}{216} \)
\( \frac{288}{125} \)
\( \frac{280}{125} \)