If the value of \( \left(1+\dfrac{2}{3}+\dfrac{6}{3^{2}}+\dfrac{10}{3^{3}}+\ldots \text{ up to } \infty \right)^{\log_{(0.25)}\!\left(\dfrac{1}{3}+\dfrac{1}{3^{2}}+\dfrac{1}{3^{3}}+\ldots \text{ up to } \infty \right)} \) is \( l \) then \( l^{2} \) is equal to __________ .
