An arithmetic progression is written in the following way
The sum of all the terms of the \( 10^{\text{th}} \) row is __________.
If \( \dfrac{1}{(20-a)(40-a)}+\dfrac{1}{(40-a)(60-a)}+\ldots+\dfrac{1}{(180-a)(200-a)}=\dfrac{1}{256} \), then the maximum value of \( a \) is:
