The sum \( 1+\dfrac{1}{2}(1^2+2^2)+\dfrac{1}{3}(1^2+2^2+3^2)+\ldots \) upto \( 10 \) terms is equal to:
\( 130 \)
\( 155 \)
\( \dfrac{315}{2} \)
\( \dfrac{325}{2} \)