Let \( a_1,a_2,a_3,\ldots \) be an A.P. If \( a_7=3 \), the product \( a_1a_4 \) is minimum and the sum of its first \( n \) terms is zero, then \( n!-4a_{n(n+2)} \) is equal to:
\( \frac{33}{4} \)
\( 24 \)
\( \frac{381}{4} \)
\( 9 \)