$\displaystyle \lim_{n\to\infty} \left[ \frac{1}{1+n} + \frac{1}{2+n} + \frac{1}{3+n} + \ldots + \frac{1}{2n} \right] \text{ is equal to :}$
\( \log_e \left( \frac{3}{2} \right) \)
\( 0 \)
\( \log_e \left( \frac{2}{3} \right) \)
\( \log_e 2 \)