\(\displaystyle \lim_{n \to \infty} \frac{1}{2^n} \left( \frac{1}{\sqrt{1-\dfrac{1}{2^n}}} + \frac{1}{\sqrt{1-\dfrac{2}{2^n}}} + \frac{1}{\sqrt{1-\dfrac{3}{2^n}}} + \ldots + \frac{1}{\sqrt{1-\dfrac{2^n-1}{2^n}}} \right) \) is equal to:
\( \dfrac{1}{2} \)
\( 1 \)
\( 2 \)
\( -2 \)
