Consider the integral \( I=\displaystyle\int\limits_{0}^{10}\dfrac{[x] \, e^{[x]}}{e^{x-1}}\,dx \), where \( [x] \) denotes the greatest integer less than or equal to \( x \). Then the value of \( I \) is equal to:
\( 9(e+1) \)
\( 45(e-1) \)
\( 9(e-1) \)
\( 45(e+1) \)