If the area of the region \( \{(x,y): \frac{a}{x^2} \le y \le \frac{1}{x}, \, 1 \le x \le 2, \, 0 <a<1\}\) is (log\(_e2\))\(-\frac{1}{7}\) then the value of \(7a-3 \)is equal to:
\( 1 \)
\( 0 \)
\( 2 \)
\( -1 \)