Let \( f:\mathbb{R}\to\mathbb{R} \) be a twice differentiable function such that \( f(2)=1 \). If \( F(x)=x f(x) \) for all \( x\in\mathbb{R} \), \(\displaystyle \int_{0}^{2} xF'(x)\,dx = 6 \) and \(\displaystyle \int_{0}^{2} x^{2}F''(x)\,dx = 40 \), then \(\displaystyle F'(2)+\int_{0}^{2} F(x)\,dx \) is equal to:
