If \( \displaystyle \int_{\pi/6}^{\pi/4}\left(\cot\!\left(x-\dfrac{\pi}{3}\right)\cot\!\left(x+\dfrac{\pi}{3}\right)+1\right)dx=\alpha \log_{e}(\sqrt{3}-1) \), then \( 9\alpha^2 \) is equal to \( \_\_\_\_\_ \).