The area of the region in the first quadrant inside the circle \( x^2+y^2=8 \) and outside the parabola \( y^2=2x \) is equal to:
\( \frac{\pi}{2}-\frac{2}{3} \)
\( \frac{\pi}{2}-\frac{1}{3} \)
\( \pi-\frac{1}{3} \)
\( \pi-\frac{2}{3} \)