The area of the region given by \( A=\{(x,y): x^2 \leq y \leq \min\{x+2,\, 4-3x\}\} \) is :
\( \dfrac{31}{8} \)
\( \dfrac{17}{6} \)
\( \dfrac{19}{6} \)
\( \dfrac{27}{8} \)