Let \( S=\{1,2,3,4,5,6\} \). Then the probability that a randomly chosen onto function \( g \) from \( S \) to \( S \) satisfies \( g(3)=2g(1) \) is:
\( \dfrac{1}{15} \)
\( \dfrac{1}{30} \)
\( \dfrac{1}{10} \)
\( \dfrac{1}{5} \)