The probability that a randomly selected \( 2 \)-digit number belongs to the set \( \{ n \in \mathbb{N} : (2^n - 2) \text{ is a multiple of } 3 \} \) is equal to:
\( \dfrac{2}{3} \)
\( \dfrac{1}{2} \)
\( \dfrac{1}{6} \)
\( \dfrac{1}{3} \)