Let a biased coin be tossed \( 5 \) times. If the probability of getting \( 4 \) heads is equal to the probability of getting \( 5 \) heads, then the probability of getting at most two heads is:
\( \dfrac{275}{6^5} \)
\( \dfrac{36}{5^4} \)
\( \dfrac{181}{5^5} \)
\( \dfrac{46}{6^4} \)