If an unbiased dice is rolled thrice, then the probability of getting a greater number in the \( i^{\text{th}} \) roll than the number obtained in the \( (i-1)^{\text{th}} \) roll, \( i = 2, 3 \) is equal to
\( {1}/{54} \)
\( {2}/{54} \)
\( {5}/{54} \)
\( {3}/{54} \)