If the probability that the random variable \( X \) takes the value \( x \) is given by \( P(X=x)=k(x+1)3^{-x} \), \( x = 0, 1, 2, 3, \ldots \) where \( k \) is a constant, then \( P(X \ge 3) \) is equal to:
\( \frac{1}{9} \)
\( \frac{4}{9} \)
\( \frac{8}{27} \)
\( \frac{7}{27} \)