Let \( N \) denote the sum of the numbers obtained when two dice are rolled. If the probability that \( 2^N < N! \) is \( \dfrac{m}{n} \), where \( m \) and \( n \) are coprime, then \( 4m - 3n \) is equal to:
\( 6 \)
\( 12 \)
\( 8 \)
\( 10 \)