A bag contains \( 6 \) blue and \( 6 \) green balls. Pairs of balls are drawn without replacement until the bag is empty. The probability that each drawn pair consists of one blue and one green ball is:
\( \dfrac{63}{925} \)
\( \dfrac{17}{231} \)
\( \dfrac{16}{231} \)
\( \dfrac{64}{925} \)