Let \( P \) be the plane containing the straight line \( \displaystyle\frac{x-3}{9}=\frac{y+4}{-1}=\frac{z-7}{-5} \) and perpendicular to the plane containing the straight lines \(\displaystyle \frac{x}{2}=\frac{y}{3}=\frac{z}{5} \) & \(\displaystyle \frac{x}{3}=\frac{y}{7}=\frac{z}{8} \). If \( d \) is the distance of \( P \) from the point \( (2,-5,11) \), then \( d^2 \) is equal to: