If the lines \( \dfrac{x-1}{1}=\dfrac{y-2}{2}=\dfrac{z+3}{1} \) and \( \dfrac{x-a}{2}=\dfrac{y+2}{3}=\dfrac{z-3}{1} \) intersect at the point \( P \), then the distance of the point \( P \) from the plane \( z=a \) is:
\( 10 \)
\( 22 \)
\( 16 \)
\( 28 \)