The shortest distance between the lines \( \frac{x-3}{2} = \frac{y-2}{3} = \frac{z-1}{-1} \) and \( \frac{x+3}{2} = \frac{y-6}{1} = \frac{z-5}{3} \), is
\( \frac{18}{\sqrt{5}} \)
\( \frac{22}{3\sqrt{5}} \)
\( \frac{46}{3\sqrt{5}} \)
\( 6\sqrt{3} \)