Let \( P \) be the point of intersection of the lines \( \dfrac{x-2}{1} = \dfrac{y-4}{5} = \dfrac{z-2}{1} \) and \( \dfrac{x-3}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{2} \). Then, the shortest distance of \( P \) from the line \( 4x = 2y = z \) is:
\( \dfrac{6\sqrt{14}}{7} \)
\( \dfrac{3\sqrt{14}}{7} \)
\( \dfrac{\sqrt{14}}{7} \)
\( \dfrac{5\sqrt{14}}{7} \)
