Let the line \( L \) pass through the point \( (0, 1, 2) \), intersect the line \( \dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{4} \) and be parallel to the plane \( 2x + y - 3z = 4 \). Then the distance of the point \( P(1, -9, 2) \) from the line \( L \) is:
