The shortest distance between the lines \( \dfrac{x+7}{-6}=\dfrac{y-6}{7}=z \) and \( \dfrac{7-x}{2}=y-2=z-6 \) is
\( 2\sqrt{29} \)
\( 1 \)
\( \sqrt{\dfrac{37}{29}} \)
\( \dfrac{\sqrt{29}}{2} \)