Let \(d\) be the distance of the point of intersection of the lines \( \dfrac{x+6}{3}=\dfrac{y}{2}=\dfrac{z+1}{1} \) and \( \dfrac{x-7}{4}=\dfrac{y-9}{3}=\dfrac{z-4}{2} \) from the point \( (7,8,9) \). Then \( d^{2}+6 \) is equal to:
\(69\)
\(78\)
\(75\)
\(72\)