If a plane passes through the points \(( -1, k, 0)\), \(( 2, k, -1)\), \(( 1, 1, 2)\) and is parallel to the line \( \dfrac{x-1}{1}=\dfrac{2y+1}{2}=\dfrac{z+1}{-1} \), then the value of \( \dfrac{k^{2}+1}{(k-1)(k-2)} \) is :
\(\dfrac{6}{13}\)
\(\dfrac{5}{17}\)
\(\dfrac{17}{5}\)
\(\dfrac{13}{6}\)