Let a straight line \( L \) pass through the point \( P(2,-1,3) \) and be perpendicular to the lines \(\displaystyle \frac{x-1}{2}=\frac{y+1}{1}=\frac{z-3}{-2} \) and \(\displaystyle \frac{x-3}{1}=\frac{y-2}{3}=\frac{z+2}{4} \). If the line \( L \) intersects the \( yz \)-plane at the point \( Q \), then the distance between the point \( P \) and \( Q \) is:
