If \( y = y(x) \) is the solution curve of the differential equation \( x^{2} dy + \left( y - \frac{1}{x} \right) dx = 0; \ x > 0 \), and \( y(1) = 1 \), then \( y\!\left( \frac{1}{2} \right) \) is equal to:
Let \( y=y_{1}(x) \) and \( y=y_{2}(x) \) be two distinct solutions of the differential equation \( \dfrac{dy}{dx}=x+y \) with \( y_{1}(0)=0 \) and \( y_{2}(0)=1 \) respectively. Then, the number of points of intersection of \( y=y_{1}(x) \) and \( y=y_{2}(x) \) is:
