Let \( x = x(y) \) be the solution of the differential equation \( 2y^2 \frac{dx}{dy} - 2xy + x^2 = 0, \; y > 1, x(e) = e \). Then \( x(e^2) \) is equal to:
\( \frac{3}{2} e^2 \)
\( \frac{2}{3} e^2 \)
\( e^2 \)
\( 2 e^2 \)