Let \( y = y(x) \) be the solution of the differential equation \( (2x \log_e x)\,\frac{dy}{dx} + 2y = \frac{3}{x}\log_e x ,\ x>0 \) and \( y(e^{-1}) = 0 \). Then, \( y(e) \) is equal to:
-\( \frac{2}{e} \)
-\( \frac{2}{3e} \)
-\( \frac{3}{2e} \)
-\( \frac{3}{e} \)