If \( \frac{dy}{dx}=\frac{2^{x+y}-2^{x}}{2^{y}},\ y(0)=1 \), then \( y(1) \) is equal to:
\( \log_{2}(1+e) \)
\( \log_{2}(2e) \)
\( \log_{2}(2+e) \)
\( \log_{2}(1+e^{2}) \)