Let \( y = y(x) \) be the solution curve of the differential equation \( (1 + x^2)\,dy + \left(y - \tan^{-1}x\right)dx = 0,\, y(0) = 1 \). Then the value of \( y(1) \) is:
\( \frac{4}{e^{\pi/2}} + \frac{\pi}{2} - 1 \)
\( \frac{2}{e^{\pi/4}} + \frac{\pi}{4} - 1 \)
\( \frac{2}{e^{\pi/4}} - \frac{\pi}{4} - 1 \)
\( \frac{4}{e^{\pi/2}} - \frac{\pi}{2} - 1 \)