Let \( y(x) \) be the solution of the differential equation \( 2x^2 dy + (e^y - 2x)dx = 0, \, x>0 \). If \( y(e)=1 \), then \( y(1) \) is equal to:
\( \log_e 2 \)
\( \log_e (2e) \)
\( 2 \)
\( 0 \)