Surface tension of a soap bubble is \( 2.0 \times 10^{-2} \, \text{N m}^{-1} \). Work done to increase the radius of soap bubble from \( 3.5 \, \text{cm} \) to \( 7 \, \text{cm} \) will be: Take \( \left[ \pi = \frac{22}{7} \right] \)
\( 5.76 \times 10^{-4} \, \text{J} \)
\( 18.48 \times 10^{-4} \, \text{J} \)
\( 0.72 \times 10^{-4} \, \text{J} \)
\( 9.24 \times 10^{-4} \, \text{J} \)