A water drop of diameter \( 2 \, \text{cm} \) is broken into \( 64 \) equal droplets. The surface tension of water is \( 0.075 \, \text{N/m} \). In this process the gain in surface energy will be:
\( 2.8 \times 10^{-4} \, \text{J} \)
\( 1.5 \times 10^{-3} \, \text{J} \)
\( 1.9 \times 10^{-4} \, \text{J} \)
\( 9.4 \times 10^{-5} \, \text{J} \)