Let \( A(2,3,5) \) and \( C(-3,4,-2) \) be opposite vertices of a parallelogram \( ABCD \). If the diagonal \( \overrightarrow{BD} = \hat{i} + 2\hat{j} + 3\hat{k} \), then the area of the parallelogram is equal to:
\( \frac{1}{2}\sqrt{410} \)
\( \frac{1}{2}\sqrt{306} \)
\( \frac{1}{2}\sqrt{586} \)
\( \frac{1}{2}\sqrt{474} \)