Let \( \vec{a} \) and \( \vec{b} \) be two vectors such that \( |\vec{a}| = \sqrt{14} \), \( |\vec{b}| = \sqrt{6} \) and \( |\vec{a} \times \vec{b}| = \sqrt{48} \). Then \( (\vec{a} \cdot \vec{b})^{2} \) is equal to _____.