When vector \( \vec{A} = 2\hat{i} + 3\hat{j} + 2\hat{k} \) is subtracted from vector \( \vec{B} \), it gives a vector equal to \( 2\hat{j} \). Then the magnitude of vector \( \vec{B} \) will be :
\( \sqrt{13} \)
\( \sqrt{5} \)
\( \sqrt{33} \)
\( \sqrt{6} \)